c^2-4c+13=

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Solution for c^2-4c+13= equation:


Simplifying
c2 + -4c + 13 = 0

Reorder the terms:
13 + -4c + c2 = 0

Solving
13 + -4c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + -4c + -13 + c2 = 0 + -13

Reorder the terms:
13 + -13 + -4c + c2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -4c + c2 = 0 + -13
-4c + c2 = 0 + -13

Combine like terms: 0 + -13 = -13
-4c + c2 = -13

The c term is -4c.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4c + 4 + c2 = -13 + 4

Reorder the terms:
4 + -4c + c2 = -13 + 4

Combine like terms: -13 + 4 = -9
4 + -4c + c2 = -9

Factor a perfect square on the left side:
(c + -2)(c + -2) = -9

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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